There are some problems so simple that we calculate them with easy, but there are many solutions to solve that problems.
This is the nice exercise.......
Both A and B is a number. Let's assume AB + B = BA. From the following expression, which one is false... (assume that AB or BA is a number)
a.
A x B = CD, C + D = B
b.
AB x B = A01, AB x A=C1D
c.
AB+BA=1BC
Let A = 1, B = 2, C = 3, D = 4. Is it true that the statement ABCD = 4! ? (4! is a factorial)
a. True
b.
False
c.
Can't be determined
QWERTY is an integer that is not divisible by 2, 3, 5, 7, or 11. QWERTY results the remainder 1 when divided by 2. Among the possibilities that exist, which one is not the remainder of the division QWERTY with 3 ...
a.
-1
b. 2
c. 3
A, B, C represents an odd number. Which does not give results even number?
a.
((A-B)/C)A
b.
((A+B)/C)B
c.
((A x B)/C)C
! @ # $ % ^ & * ( ) is a code that represents the numbers 23, 31, 59, 71, 11, 39, 83, 67, 35, 89. Which of the following composition were not able to form a pattern of numbers?
a.
% , ! , @ , ( , (
b.
% , ! , ^ , # , &
c.
% , ! , @ , * , )
Those questions has challenged you to think out of the box...
Try to resolve it.
Solutions
C C C C C
- A = 8, B = 9
- ABCD is number or ABCD is A x B x C x D
- Possible numbers 1, 13, 17, 19
- Odd x odd = odd
- Pattern of numbers :
a (11 , 23 , 31 , 35 , 35)
+12 +8 +4 +0
b (11 , 23 , 39 , 59 , 83)
+12 +16 +20 +24
c (11 , 23 , 31 , 67 , 89)
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